Minimum sample size for weibull analysis

[rowena]

how to find the minimum sample size for weibull analysis? there is a formula, n={1/[k^beta]}x{log alpha/ log(1-p)}. where k=Tc/Tp. is that the correct formula to determine the minimum sample size? what do each term refering to?

thanks

[RS Support]

See http://www.weibull.com/LifeDataWeb/test_design.htm