Ed Smith
September 27th, 2004, 11:06 AM
Is the mean life the same as the characteristic life for the Weibull distribution (regardless of shape parameter beta)?
Dennis Craggs
September 28th, 2004, 02:00 AM
The characteristic life is a parameter of the Weibull distribution. Consider the two parameter weibull formula:
F(t) = 1 - exp(-(t/eta)^beta) where
t is time
F(t) is the fraction failed
eta is the characteristic life
beta is the shape factor (or slope)
The if t = eta, the formula reduces to
F(eta) = 1 - exp(-1) = 0.632
This means 63.2% of the population will fail when t = eta.
The mean is the expected life. This is calculate by integrating from 0 to infinity the product of the life x the probability density. This formula can be reduced to
mean life = eta * Gamma (1 + 1/beta)
where Gamma is the Gamma function. The Gamma function may be calculated using tables or popular spread sheets include a gamma function.
Look at http://www.weibull.com/AccelTestWeb/weibull_distribution.htm for a summary. Reliability text books will also contain this information.
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